The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is :
Created: 6 years ago |
Updated: 3 years ago
best des
Hints : Let the numbers be 37a and 37b
Then, 37a × 37b = 4107
ab = 3
Now, Co primes with product 3 are (1, 3)
So, the required numbers are (37 × 1, 37 × 3) = ( 37, 111)
Areater number = 111
Md Azizur Rahman
Founder of Satt
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